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Member "which-2.21/mdate-sh" (25 May 2007, 2679 Bytes) of package /linux/privat/which-2.21.tar.gz:


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    1 #!/bin/sh
    2 # Get modification time of a file or directory and pretty-print it.
    3 # Copyright (C) 1995, 1996, 1997 Free Software Foundation, Inc.
    4 # written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
    5 #
    6 # This program is free software; you can redistribute it and/or modify
    7 # it under the terms of the GNU General Public License as published by
    8 # the Free Software Foundation; either version 2, or (at your option)
    9 # any later version.
   10 #
   11 # This program is distributed in the hope that it will be useful,
   12 # but WITHOUT ANY WARRANTY; without even the implied warranty of
   13 # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
   14 # GNU General Public License for more details.
   15 #
   16 # You should have received a copy of the GNU General Public License
   17 # along with this program; if not, write to the Free Software Foundation,
   18 # Inc., 59 Temple Place - Suite 330, Boston, MA 02110-1301, USA.
   19 
   20 # Prevent date giving response in another language.
   21 LANG=C
   22 export LANG
   23 LC_ALL=C
   24 export LC_ALL
   25 LC_TIME=C
   26 export LC_TIME
   27 
   28 # Get the extended ls output of the file or directory.
   29 # On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
   30 if ls -L /dev/null 1>/dev/null 2>&1; then
   31   set - x`ls -L -l -d $1`
   32 else
   33   set - x`ls -l -d $1`
   34 fi
   35 # The month is at least the fourth argument
   36 # (3 shifts here, the next inside the loop).
   37 shift
   38 shift
   39 shift
   40 
   41 # Find the month.  Next argument is day, followed by the year or time.
   42 month=
   43 until test $month
   44 do
   45   shift
   46   case $1 in
   47     Jan) month=January; nummonth=1;;
   48     Feb) month=February; nummonth=2;;
   49     Mar) month=March; nummonth=3;;
   50     Apr) month=April; nummonth=4;;
   51     May) month=May; nummonth=5;;
   52     Jun) month=June; nummonth=6;;
   53     Jul) month=July; nummonth=7;;
   54     Aug) month=August; nummonth=8;;
   55     Sep) month=September; nummonth=9;;
   56     Oct) month=October; nummonth=10;;
   57     Nov) month=November; nummonth=11;;
   58     Dec) month=December; nummonth=12;;
   59   esac
   60 done
   61 
   62 day=$2
   63 
   64 # Here we have to deal with the problem that the ls output gives either
   65 # the time of day or the year.
   66 case $3 in
   67   *:*) set `date`; eval year=\$$#
   68        case $2 in
   69      Jan) nummonthtod=1;;
   70      Feb) nummonthtod=2;;
   71      Mar) nummonthtod=3;;
   72      Apr) nummonthtod=4;;
   73      May) nummonthtod=5;;
   74      Jun) nummonthtod=6;;
   75      Jul) nummonthtod=7;;
   76      Aug) nummonthtod=8;;
   77      Sep) nummonthtod=9;;
   78      Oct) nummonthtod=10;;
   79      Nov) nummonthtod=11;;
   80      Dec) nummonthtod=12;;
   81        esac
   82        # For the first six month of the year the time notation can also
   83        # be used for files modified in the last year.
   84        if (expr $nummonth \> $nummonthtod) > /dev/null;
   85        then
   86      year=`expr $year - 1`
   87        fi;;
   88   *) year=$3;;
   89 esac
   90 
   91 # The result.
   92 echo $day $month $year